Method 1- Common Bases:
3^2x = 27^3x-1 1) Find Common Base
3^2x = (3^3)^ 3x-1
3^2x = 3^9x-3 2) Drop the Base
2x = 9x-3
3 = 7x 3) Solve
3/7 = x
Check:
3^3/7 = 27^3(3/7) -1
2.55 = 2.55
correct!
Method 2- Logs:
3^2x = 27^3x-1 1) Log both sides
log3^2x = log27^3x-1
2xlog3 = (3x-1)log27 2) Factor out brackets
2xlog3= 3xlog27 - log27
2xlog3- 3xlog27= -log27 3) Factor Out x
x ( 2log3 - 3log27) = -log27 4) Solve for x
(2log3- 3log27) (2log3- 3log27)
x= 0.42857
x= 3/7
*Note: when using calculator, remember to use brackets or the answer may be wrong*
No comments:
Post a Comment