Today's lesson had two methods for solving equations, log= # and log=log
Method 1: Log = #
Example:
log(2)x = 3 1) Put into (b)^E = A form
log(2)x = 3 1) Put into (b)^E = A form
2^3 = x
x = 8
Example:
log(5)(x-3)+ log(5)x = log(5)10
x(x-3) = 10
x^2- 3x = 10 2) Multiply both sides by x
x^2-3x-10 = 0
(x-5)(x+2) = 0 3) Simplify
x = 5, x = 5
*Note: negative answers are tricky, they must become positive in original equation or are rejected.*
Method 2: log = log
log5(x-3) + log5x = log5 10 1) Create only one log
log5(x-3)x = log5 10 2) Drop logs
(x-3)x = 10
x^2 - 3x = 10
x^2 -3x -10 = 0
(x-5)(x+2)
x= 5, -2 *-2 rejects*
x=5
Identities:
Equation vs. Identity
2x+3 = 5 x + x = 2x
x=1 x = all real numbers
x= specific # rejects allowed
Prove the identity and state the value(s) of x for which it is true: (make both sides equal)
logx + log(x +3) = log(x^2 +3x)
LEFT SIDE RIGHT SIDE
Left side: logx(x+3)
logx^2 + 3x = Right side
*x must be great the 0 x>0*