Formula:
tn = ar^n-1
tn - value
n - the position
r - multiplier (2nd/1st)
Example: 2, 6, 18, 54,......
1) t10
tn = 2(3)^9
tn = 39 366
2) How many terms are in the following sequence? 8, 12, 18, 27,...... 205.03125
205.03125 = 8(1.5)^n-1
8 8
log(25.6289) = (n-1) log(1.5)
log(1.5) log(1.5)
8 = n-1
9 = n
Series:
A series is the sum of a sequence
S= add t= find number
Formula:
Sn = a(1 - r^n) or Sn = a- rl
1-r 1-r
Sn: series (sum)
r: ratio
l: last term> tn
a: first #
n: how many terms there is
Example:
1) Find the sum of the series 5 + 15+ 45 +.......... + 885 735
Sn = a - rl
1-r
Sn= 5 - 3(885 735)
1-3
= 1, 328, 600
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